JEE MAIN - Physics (2022 - 24th June Evening Shift - No. 18)
Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be :
2 : 3
16 : 81
25 : 169
25 : 1
Explanation
$${{{I_{\max }}} \over {{I_{\min }}}} = {\left( {{{\sqrt {{I_1}} + \sqrt {{I_2}} } \over {\sqrt {{I_1}} - \sqrt {{I_2}} }}} \right)^2} = {\left( {{5 \over 1}} \right)^2}$$
$$ = {{25} \over 1}$$
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