JEE MAIN - Physics (2022 - 24th June Evening Shift - No. 13)
A 100 g of iron nail is hit by a 1.5 kg hammer striking at a velocity of 60 ms$$-$$1. What will be the rise in the temperature of the nail if one fourth of energy of the hammer goes into heating the nail?
[Specific heat capacity of iron = 0.42 Jg$$-$$1 $$^\circ$$C$$-$$1]
675$$^\circ$$C
1600$$^\circ$$C
16.07$$^\circ$$C
6.75$$^\circ$$C
Explanation
$${1 \over 2} \times 1.5 \times {60^2} \times {1 \over 4} = 100 \times 0.42 \times \Delta T$$
$$\Delta T = {{1.5 \times {{60}^2}} \over {8 \times 100 \times 0.42}} = 16.07^\circ C$$
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