JEE MAIN - Physics (2021 - 31st August Morning Shift - No. 26)
A capacitor of 50 $$\mu$$F is connected in a circuit as shown in figure. The charge on the upper plate of the capacitor is ______________$$\mu$$C.
_31st_August_Morning_Shift_en_26_1.png)
Answer
100
Explanation
_31st_August_Morning_Shift_en_26_2.png)
Potential Difference across each resistor = 2V
q = CV
= 50 $$\times$$ 10$$-$$6 $$\times$$ 2 = 100 $$\times$$ 10$$-$$6 = 100 $$\mu$$C
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