JEE MAIN - Physics (2021 - 31st August Morning Shift - No. 11)
Two plane mirrors M1 and M2 are at right angle to each other shown. A point source 'P' is placed at 'a' and '2a' meter away from M1 and M2 respectively. The shortest distance between the images thus formed is : (Take $$\sqrt 5 $$ = 2.3)
_31st_August_Morning_Shift_en_11_1.png)
3a
4.6a
2.3a
2$$\sqrt {10} $$a
Explanation
_31st_August_Morning_Shift_en_11_2.png)
Shortest distance is 2a between I1 & I3
But answer given is for I1 & I2
= $$\sqrt {{{(4a)}^2} + {{(2a)}^2}} $$
= $$a\sqrt {20} $$
= 4.47 a
Option (b)
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