JEE MAIN - Physics (2021 - 31st August Evening Shift - No. 27)
At very high frequencies, the effective impendence of the given circuit will be ________________ $$\Omega$$.
_31st_August_Evening_Shift_en_27_1.png)
Answer
2
Explanation
XL = 2$$\pi$$fL
f is very large
$$\therefore$$ XL is very large hence open circuit.
$${X_C} = {1 \over {2\pi fC}}$$
f is very large.
$$\therefore$$ XC is very small, hence short circuit.
Final circuit
_31st_August_Evening_Shift_en_27_2.png)
$$ \therefore $$ $${Z_{eq}} = 1 + {{2 \times 2} \over {2 + 2}} = 2$$
f is very large
$$\therefore$$ XL is very large hence open circuit.
$${X_C} = {1 \over {2\pi fC}}$$
f is very large.
$$\therefore$$ XC is very small, hence short circuit.
Final circuit
$$ \therefore $$ $${Z_{eq}} = 1 + {{2 \times 2} \over {2 + 2}} = 2$$
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