JEE MAIN - Physics (2021 - 31st August Evening Shift - No. 23)
A particle is moving with constant acceleration 'a'. Following graph shows v2 versus x(displacement) plot. The acceleration of the particle is ___________ m/s2.
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Answer
1
Explanation
y = mx + C
v2 = $${{20} \over {10}}$$x + 20
v2 = 2x + 20
2v$${{dv} \over {dx}}$$ = 2
$$\therefore$$ a = v$${{dv} \over {dx}}$$ = 1
v2 = $${{20} \over {10}}$$x + 20
v2 = 2x + 20
2v$${{dv} \over {dx}}$$ = 2
$$\therefore$$ a = v$${{dv} \over {dx}}$$ = 1
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