JEE MAIN - Physics (2021 - 31st August Evening Shift - No. 15)
A mixture of hydrogen and oxygen has volume 500 cm3, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be :-
3 : 8
3 : 16
16 : 3
8 : 3
Explanation
PV = nRT
400 $$\times$$ 103 $$\times$$ 500 $$\times$$ 10$$-$$6 = n$$\left( {{{25} \over 3}} \right)$$ (300)
n = $${{2 \over {25}}}$$
n = n1 + n2
$${{2 \over {25}}}$$ = $${{{M_1}} \over 2} + {{{M_2}} \over {32}}$$
Also, M1 + M2 = 0.76 gm
$${{{M_2}} \over {{M_1}}} = {{16} \over 3}$$
400 $$\times$$ 103 $$\times$$ 500 $$\times$$ 10$$-$$6 = n$$\left( {{{25} \over 3}} \right)$$ (300)
n = $${{2 \over {25}}}$$
n = n1 + n2
$${{2 \over {25}}}$$ = $${{{M_1}} \over 2} + {{{M_2}} \over {32}}$$
Also, M1 + M2 = 0.76 gm
$${{{M_2}} \over {{M_1}}} = {{16} \over 3}$$
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