JEE MAIN - Physics (2021 - 31st August Evening Shift - No. 11)
If velocity [V], time [T] and force [F] are chosen as the base quantities, the dimensions of the mass will be :
[FT$$-$$1 V$$-$$1]
[FTV$$-$$1]
[FT2 V]
[FVT$$-$$1]
Explanation
[M] = K[F]a [T]b [V]c
[M1] = [M1L1T$$-$$2]a [T1]b [L1T$$-$$1]c
a = 1, b = 1, c = $$-$$1
$$\therefore$$ [M] = [FTV$$-$$1]
[M1] = [M1L1T$$-$$2]a [T1]b [L1T$$-$$1]c
a = 1, b = 1, c = $$-$$1
$$\therefore$$ [M] = [FTV$$-$$1]
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