JEE MAIN - Physics (2021 - 27th July Morning Shift - No. 19)
Consider an electrical circuit containing a two way switch 'S'. Initially S is open and then T1 is connected to T2. As the current in R = 6$$\Omega$$ attains a maximum value of steady state level, T1 is disconnected from T2 and immediately connected to T3. Potential drop across r = 3$$\Omega$$ resistor immediately after T1 is connected to T3 is __________ V. (Round off to the Nearest Integer)
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Answer
3
Explanation
What T1 and T2 are connected, then the steady state current in the inductor $$I = {6 \over 6} = 1A$$
When T1 and T3 are connected then current through inductor remains same. So potential difference across 3$$\Omega$$
V = Ir = 1 $$\times$$ 3 = 3 Volt
When T1 and T3 are connected then current through inductor remains same. So potential difference across 3$$\Omega$$
V = Ir = 1 $$\times$$ 3 = 3 Volt
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