JEE MAIN - Physics (2021 - 27th July Morning Shift - No. 14)
Two capacitors of capacities 2C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C is filled completely with a medium of dielectric constant K. The potential difference across the capacitors will now be :
$${V \over {K + 2}}$$
$${V \over K}$$
$${{3V} \over {K + 2}}$$
$${{3V} \over K}$$
Explanation
_27th_July_Morning_Shift_en_14_2.png)
$${V_C} = {{2CV + CV} \over {KC + 2C}}$$
$$ = {{3V} \over {K + 2}}$$
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