JEE MAIN - Physics (2021 - 27th July Morning Shift - No. 10)
In the reported figure, there is a cyclic process ABCDA on a sample of 1 mol of a diatomic gas. The temperature of the gas during the process A $$\to$$ B and C $$\to$$ D are T1 and T2 (T1 > T2) respectively.
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Choose the correct option out of the following for work done if processes BC and DA are adiabatic.
Choose the correct option out of the following for work done if processes BC and DA are adiabatic.
WAB = WDC
WAD = WBC
WBC + WDA > 0
WAB < WCD
Explanation
Work done in adiabatic process = $${{ - nR} \over {\gamma - 1}}({T_f} - {T_i})$$
$$\therefore$$ $${W_{AD}} = {{ - nR} \over {\gamma - 1}}({T_2} - {T_1})$$
and $${W_{BC}} = {{ - nR} \over {\gamma - 1}}({T_2} - {T_1})$$
$$\therefore$$ $${W_{AD}} = {W_{BC}}$$
$$\therefore$$ $${W_{AD}} = {{ - nR} \over {\gamma - 1}}({T_2} - {T_1})$$
and $${W_{BC}} = {{ - nR} \over {\gamma - 1}}({T_2} - {T_1})$$
$$\therefore$$ $${W_{AD}} = {W_{BC}}$$
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