JEE MAIN - Physics (2021 - 27th July Evening Shift - No. 19)
In the given figure, two wheels P and Q are connected by a belt B. The radius of P is three times as that of Q. In case of same rotational kinetic energy, the ratio of rotational inertias $$\left( {{{{I_1}} \over {{I_2}}}} \right)$$ will be x : 1. The value of x will be _____________.
_27th_July_Evening_Shift_en_19_1.png)
Answer
9
Explanation
_27th_July_Evening_Shift_en_19_2.png)
$${1 \over 2}{I_1}{({\omega _1})^2} = {1 \over 2}{I_2}{({\omega _2})^2}$$
$${I_1}{\left( {{v \over {3R}}} \right)^2} = {I_2}{\left( {{v \over R}} \right)^2}$$
$${{{I_1}} \over {{I_2}}} = {9 \over 1}$$
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