JEE MAIN - Physics (2021 - 27th August Morning Shift - No. 9)
Moment of inertia of a square plate of side l about the axis passing through one of the corner and perpendicular to the plane of square plate is given by :
$${{M{l^2}} \over 6}$$
$${M{l^2}}$$
$${{M{l^2}} \over {12}}$$
$${2 \over 3}M{l^2}$$
Explanation
According to perpendicular Axis theorem.
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Ix + Iy = Iz
Iz $$\Rightarrow$$ $${{m{l^2}} \over 3} + {{m{l^2}} \over 3}$$
$$ = {{2m{l^2}} \over 3}$$
Ix + Iy = Iz
Iz $$\Rightarrow$$ $${{m{l^2}} \over 3} + {{m{l^2}} \over 3}$$
$$ = {{2m{l^2}} \over 3}$$
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