JEE MAIN - Physics (2021 - 27th August Morning Shift - No. 8)
Calculate the amount of charge on capacitor of 4$$\mu$$F. The internal resistance of battery is 1$$\Omega$$ :
_27th_August_Morning_Shift_en_8_1.png)
8 $$\mu$$C
zero
16 $$\mu$$C
4 $$\mu$$C
Explanation
On simplifying circuit we get
_27th_August_Morning_Shift_en_8_2.png)
No current in upper wire.
$$\therefore$$ $${V_{AB}} = {5 \over {4 + 1}} \times 4 = 4$$ v
$$\therefore$$ $$\theta$$ = (Ceq)v
$$\Rightarrow$$ 2 $$\times$$ 4 = 8 $$\mu$$C
No current in upper wire.
$$\therefore$$ $${V_{AB}} = {5 \over {4 + 1}} \times 4 = 4$$ v
$$\therefore$$ $$\theta$$ = (Ceq)v
$$\Rightarrow$$ 2 $$\times$$ 4 = 8 $$\mu$$C
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