JEE MAIN - Physics (2021 - 27th August Morning Shift - No. 25)
Two persons A and B perform same amount of work in moving a body through a certain distance d with application of forces acting at angle 45$$^\circ$$ and 60$$^\circ$$ with the direction of displacement respectively. The ratio of force applied by person A to the force applied by person B is $${1 \over {\sqrt x }}$$. The value of x is .................... .
Answer
2
Explanation
Given WA = WB
FAd cos45$$^\circ$$ = FBd cos60$$^\circ$$
$${F_A} \times {1 \over {\sqrt 2 }} = {F_B} \times {1 \over 2}$$
$${{{F_A}} \over {{F_B}}} = {{\sqrt 2 } \over 2} = {1 \over {\sqrt 2 }}$$
x = 2
FAd cos45$$^\circ$$ = FBd cos60$$^\circ$$
$${F_A} \times {1 \over {\sqrt 2 }} = {F_B} \times {1 \over 2}$$
$${{{F_A}} \over {{F_B}}} = {{\sqrt 2 } \over 2} = {1 \over {\sqrt 2 }}$$
x = 2
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