JEE MAIN - Physics (2021 - 27th August Morning Shift - No. 16)
Electric field in a plane electromagnetic wave is given by E = 50 sin(500x $$-$$ 10 $$\times$$ 1010 t) V/m The velocity of electromagnetic wave in this medium is :
(Given C = speed of light in vacuum)
(Given C = speed of light in vacuum)
$${3 \over 2}$$C
C
$${2 \over 3}$$C
$${C \over 2}$$
Explanation
$$V = {\omega \over K} = {{10 \times {{10}^{10}}} \over {500}} = 2 \times {10^8}$$
$$V = {{2C} \over 3}$$.
$$V = {{2C} \over 3}$$.
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