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JEE MAIN - Physics (2021 - 27th August Evening Shift - No. 5)

Three capacitors C1 = 2$$\mu$$F, C2 = 6$$\mu$$F and C3 = 12$$\mu$$F are connected as shown in figure. Find the ratio of the charges on capacitors C1, C2 and C3 respectively :

JEE Main 2021 (Online) 27th August Evening Shift Physics - Capacitor Question 72 English
2 : 1 : 1
2 : 3 : 3
1 : 2 : 2
3 : 4 : 4

Explanation

JEE Main 2021 (Online) 27th August Evening Shift Physics - Capacitor Question 72 English Explanation
(VD $$-$$ V) C2 + (VD $$-$$ 0) C3 = 0

(VD $$-$$ V) 6 + (VD $$-$$ 0) 12 = 0

VD $$-$$ V + 2VD = 0

VD = $${V \over 3}$$

q2 = (V $$-$$ VD) C2 = $$\left( {V - {V \over 3}} \right)$$ (6 $$\mu$$F)

q2 = (4V) $$\mu$$F

q3 = (VD $$-$$ 0) C3 = $${{V \over 3}}$$ $$\times$$ 12$$\mu$$F = 4V$$\mu$$F

q1 = (V $$-$$ 0) C1 = V(2$$\mu$$F)

q1 : q2 : q3 = 2 : 4 : 4

q1 : q2 : q3 = 1 : 2 : 2

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