JEE MAIN - Physics (2021 - 27th August Evening Shift - No. 20)
A zener diode of power rating 2W is to be used as a voltage regulator. If the zener diode has a breakdown of 10 V and it has to regulate voltage fluctuated between 6 V and 14 V, the value of Rs for safe operation should be ___________ $$\Omega$$.
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Answer
20
Explanation
When unregulated voltage is 14 V voltage across zener diode must be 10 V. So potential difference across resistor $$\Delta$$VRs = 4V
and Pzener = 2W
VI = 2
I = $${2 \over {10}}$$ = 0.2 A
$$\Delta$$VRs = I Rs
4 $$\times$$ 0.2 Rs $$\Rightarrow$$ Rs = $${40 \over {2}}$$ = 20$$\Omega$$
and Pzener = 2W
VI = 2
I = $${2 \over {10}}$$ = 0.2 A
$$\Delta$$VRs = I Rs
4 $$\times$$ 0.2 Rs $$\Rightarrow$$ Rs = $${40 \over {2}}$$ = 20$$\Omega$$
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