JEE MAIN - Physics (2021 - 27th August Evening Shift - No. 15)
A player kicks a football with an initial speed of 25 ms$$-$$1 at an angle of 45$$^\circ$$ from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g = 10 ms$$-$$2)
hmax = 10 m
T = 2.5 s
T = 2.5 s
hmax = 15.625 m
T = 3.54 s
T = 3.54 s
hmax = 15.625 m
T = 1.77 s
T = 1.77 s
hmax = 3.54 m
T = 0.125 s
T = 0.125 s
Explanation
$$H = {{{U^2}{{\sin }^2}\theta } \over {2g}}$$
$$ = {{{{(25)}^2}.{{(\sin 45)}^2}} \over {2 \times 10}}$$
= 15.625 m
$$T = {{U\sin \theta } \over g}$$
$$ = {{25 \times \sin 45^\circ } \over {10}}$$
= 2.5 $$\times$$ 0.7
= 1.77 s
$$ = {{{{(25)}^2}.{{(\sin 45)}^2}} \over {2 \times 10}}$$
= 15.625 m
$$T = {{U\sin \theta } \over g}$$
$$ = {{25 \times \sin 45^\circ } \over {10}}$$
= 2.5 $$\times$$ 0.7
= 1.77 s
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