JEE MAIN - Physics (2021 - 27th August Evening Shift - No. 14)
The height of victoria falls is 63 m. What is the difference in temperature of water at the top and at the bottom of fall?
[Given 1 cal = 4.2 J and specific heat of water = 1 cal g$$-$$1 $$^\circ$$0C$$-$$1]
[Given 1 cal = 4.2 J and specific heat of water = 1 cal g$$-$$1 $$^\circ$$0C$$-$$1]
0.147$$^\circ$$ C
14.76$$^\circ$$ C
1.476$$^\circ$$ C
0.014$$^\circ$$ C
Explanation
Change in P.E. = Heat energy
mgh = mS$$\Delta$$T
$$\Delta$$T = $${{gh} \over S}$$
= $${{10 \times 63} \over {4200J/kgC}}$$
= 0.147$$^\circ$$C
mgh = mS$$\Delta$$T
$$\Delta$$T = $${{gh} \over S}$$
= $${{10 \times 63} \over {4200J/kgC}}$$
= 0.147$$^\circ$$C
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