JEE MAIN - Physics (2021 - 26th February Evening Shift - No. 23)
The zener diode has a Vz = 30V. The current passing through the diode for the following circuit is ________ mA.
_26th_February_Evening_Shift_en_23_1.png)
_26th_February_Evening_Shift_en_23_1.png)
Answer
9
Explanation
_26th_February_Evening_Shift_en_23_2.png)
$$I = {{90 - 30} \over 4} = 15mA$$
$${I_1} = {{30} \over {5K\Omega }} = 6mA$$
$${I_2} = 15mA - 6mA = 9mA$$
Comments (0)
