JEE MAIN - Physics (2021 - 26th August Morning Shift - No. 18)
If E, L, M and G denote the quantities as energy, angular momentum, mass and constant of gravitation respectively, then the dimensions of P in the formula P = EL2M$$-$$5G$$-$$2 are :
[M0 L1 T0]
[M$$-$$1 L$$-$$1 T2]
[M1 L1 T$$-$$2]
[M0 L0 T0]
Explanation
E = ML2T$$-$$2
L = ML2T$$-$$1
m = M
G = M$$-$$1L+3T$$-$$2
P = $${{E{L^2}} \over {{M^5}{G^2}}}$$
[P] = $${{(M{L^2}{T^{ - 2}})({M^2}{L^4}{T^{ - 2}})} \over {{M^5}({M^{ - 2}}{L^6}{T^{ - 4}})}} = {M^0}{L^0}{T^0}$$
L = ML2T$$-$$1
m = M
G = M$$-$$1L+3T$$-$$2
P = $${{E{L^2}} \over {{M^5}{G^2}}}$$
[P] = $${{(M{L^2}{T^{ - 2}})({M^2}{L^4}{T^{ - 2}})} \over {{M^5}({M^{ - 2}}{L^6}{T^{ - 4}})}} = {M^0}{L^0}{T^0}$$
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