JEE MAIN - Physics (2021 - 26th August Morning Shift - No. 13)
A solid metal sphere of radius R having charge q is enclosed inside the concentric spherical shell of inner radius a and outer radius b as shown in the figure. The approximate variation electric field $$\overrightarrow E $$ as a function of distance r from centre O is given by
_26th_August_Morning_Shift_en_13_1.png)
_26th_August_Morning_Shift_en_13_2.png)
_26th_August_Morning_Shift_en_13_3.png)
_26th_August_Morning_Shift_en_13_4.png)
_26th_August_Morning_Shift_en_13_5.png)
Explanation
Considering outer spherical shell is non-conducting.
Electric field inside a metal sphere is zero.
r < R $$\Rightarrow$$ E = 0
r > R $$\Rightarrow$$ E = $${{kQ} \over {{r^2}}}$$
_26th_August_Morning_Shift_en_13_6.png)
Option (b)
Considering outer spherical shell is conducting
_26th_August_Morning_Shift_en_13_7.png)
r < R, E = 0
R $$\le$$ r < a
E = $${{kQ} \over {{r^2}}}$$
a$$\le$$ r < b,
E = 0
r $$\ge$$ b,
E = $${{kQ} \over {{r^2}}}$$
_26th_August_Morning_Shift_en_13_8.png)
Electric field inside a metal sphere is zero.
r < R $$\Rightarrow$$ E = 0
r > R $$\Rightarrow$$ E = $${{kQ} \over {{r^2}}}$$
Option (b)
Considering outer spherical shell is conducting
r < R, E = 0
R $$\le$$ r < a
E = $${{kQ} \over {{r^2}}}$$
a$$\le$$ r < b,
E = 0
r $$\ge$$ b,
E = $${{kQ} \over {{r^2}}}$$
Comments (0)
