JEE MAIN - Physics (2021 - 26th August Morning Shift - No. 12)
In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6$$\Omega$$. Calculate the power dissipated in the whole circuit :
_26th_August_Morning_Shift_en_12_1.png)
1.32 W
0.65 W
2.2 W
4.4 W
Explanation
_26th_August_Morning_Shift_en_12_2.png)
_26th_August_Morning_Shift_en_12_3.png)
$${1 \over {{R_{eq}}}} = {1 \over 4} + {1 \over 8} + {1 \over {12}} + {1 \over 6} = {{6 + 3 + 2 + 4} \over {24}} = {{15} \over {24}}$$
$${R_{eq}} = {{24} \over {15}} = 1.6 \Rightarrow {R_T} = 1.6 + 0.6 = 2.2\,\Omega $$
$$P = {{{V^2}} \over {{R_T}}} = {{{{(2.2)}^2}} \over {2.2}} = 2.2W$$
Option (c)
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