JEE MAIN - Physics (2021 - 26th August Evening Shift - No. 27)
The coefficient of static friction between two blocks is 0.5 and the table is smooth. The maximum horizontal force that can be applied to move the blocks together is .................. N. (take g = 10 ms-2)
_26th_August_Evening_Shift_en_27_1.png)
Answer
15
Explanation
F = 3a (For system) ............ (i)
_26th_August_Evening_Shift_en_27_2.png)
fsmax = 1a (for 1 kg block) ............ (ii)
$$\mu$$ $$\times$$ 1 $$\times$$ g = a
F = 15N
fsmax = 1a (for 1 kg block) ............ (ii)
$$\mu$$ $$\times$$ 1 $$\times$$ g = a
F = 15N
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