JEE MAIN - Physics (2021 - 26th August Evening Shift - No. 25)
For the given circuit, the power across Zener diode is .............. mW.
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Answer
120
Explanation
_26th_August_Evening_Shift_en_25_3.png)
$$i = {{10V} \over {5k\Omega }}$$ = 2mA
$$I = {{14V} \over {1k\Omega }}$$ = 14 mA
$$\therefore$$ Iz = 12 mA
$$\therefore$$ P = IzVz = 120 mW
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