JEE MAIN - Physics (2021 - 26th August Evening Shift - No. 16)
If the length of the pendulum in pendulum clock increases by 0.1%, then the error in time per day is :
86.4 s
4.32 s
43.2 s
8.64 s
Explanation
$$T = 2\pi \sqrt {{l \over g}} $$
$${{\Delta T} \over T} = {1 \over 2}{{\Delta l} \over l}$$
$$\Delta T = {1 \over 2} \times {{0.1} \over {100}} \times 24 \times 3600$$
$$\Delta T = 43.2$$
$${{\Delta T} \over T} = {1 \over 2}{{\Delta l} \over l}$$
$$\Delta T = {1 \over 2} \times {{0.1} \over {100}} \times 24 \times 3600$$
$$\Delta T = 43.2$$
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