JEE MAIN - Physics (2021 - 26th August Evening Shift - No. 12)
An electric bulb of 500 watt at 100 volt is used in a circuit having a 200 V supply. Calculate the resistance R to be connected in series with the bulb so that the power delivered by the bulb is 500 W.
20 $$\Omega$$
30 $$\Omega$$
5 $$\Omega$$
10 $$\Omega$$
Explanation
500 watt at 100 v
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P = Vi
500 = Vi
i = 5 Amp
V = i $$\times$$ R
R = 20
P = Vi
500 = Vi
i = 5 Amp
V = i $$\times$$ R
R = 20
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