JEE MAIN - Physics (2021 - 26th August Evening Shift - No. 1)
The temperature of equal masses of three different liquids x, y and z are 10$$^\circ$$C, 20$$^\circ$$C and 30$$^\circ$$C respectively. The temperature of mixture when x is mixed with y is 16$$^\circ$$C and that when y is mixed with z is 26$$^\circ$$C. The temperature of mixture when x and z are mixed will be :
28.32$$^\circ$$C
25.62$$^\circ$$C
23.84$$^\circ$$C
20.28$$^\circ$$C
Explanation
_26th_August_Evening_Shift_en_1_2.png)
when x and y are mixed, Tf1 = 16$$^\circ$$C
m1s1T + m2s2T2 = (m1s1 + m2s2)Tf1
s1 $$\times$$ 10 + s2 $$\times$$ 20 = (s1 + s2) $$\times$$ 16
s1 = $${2 \over 3}$$s2 .... (i)
when y and z are mixed, Tf2 = 26$$^\circ$$C
m2s2T + m3s3T3 = (m3s3 + m3s3)Tf2
s2 $$\times$$ 20 + s3 $$\times$$ 30 = (s2 + s3) $$\times$$ 26
s3 = $${3 \over 2}$$s2 ..... (ii)
when x and z are mixed
m1s1T1 + m3s3T3 = (m1s1 + m3s3)Tf
$${2 \over 3}$$s2 $$\times$$ 10 + $${2 \over 3}$$s2 $$\times$$ 20 = $$\left( {{2 \over 3}{s_2} + {3 \over 2}{s_2}} \right){T_f}$$
Tf = 23.84$$^\circ$$C
Comments (0)
