JEE MAIN - Physics (2021 - 25th July Morning Shift - No. 13)
Two different metal bodies A and B of equal mass are heated at a uniform rate under similar conditions. The variation of temperature of the bodies is graphically represented as shown in the figure. The ratio of specific heat capacities is :
_25th_July_Morning_Shift_en_13_1.png)
$${8 \over 3}$$
$${3 \over 8}$$
$${3 \over 4}$$
$${4 \over 3}$$
Explanation
$${\left( {{{\Delta Q} \over {\Delta t}}} \right)_A} = {\left( {{{\Delta Q} \over {\Delta t}}} \right)_B}$$
$$m{S_A}{\left( {{{\Delta T} \over {\Delta t}}} \right)_A} = m{S_B}{\left( {{{\Delta T} \over {\Delta t}}} \right)_B}$$
$$ \Rightarrow $$ $${{{S_A}} \over {{S_B}}} = {{{{\left( {{{\Delta T} \over {\Delta t}}} \right)}_B}} \over {{{\left( {{{\Delta T} \over {\Delta t}}} \right)}_B}}} = {{90/6} \over {120/3}} = {{15} \over {40}} = {3 \over 8}$$
$$m{S_A}{\left( {{{\Delta T} \over {\Delta t}}} \right)_A} = m{S_B}{\left( {{{\Delta T} \over {\Delta t}}} \right)_B}$$
$$ \Rightarrow $$ $${{{S_A}} \over {{S_B}}} = {{{{\left( {{{\Delta T} \over {\Delta t}}} \right)}_B}} \over {{{\left( {{{\Delta T} \over {\Delta t}}} \right)}_B}}} = {{90/6} \over {120/3}} = {{15} \over {40}} = {3 \over 8}$$
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