JEE MAIN - Physics (2021 - 25th July Evening Shift - No. 10)
Two ideal electric dipoles A and B, having their dipole moment p1 and p2 respectively are placed on a plane with their centres at O as shown in the figure. At point C on the axis of dipole A, the resultant electric field is making an angle of 37$$^\circ$$ with the axis. The ratio of the dipole moment of A and B, $${{{p_1}} \over {{p_2}}}$$ is : (take $$\sin 37^\circ = {3 \over 5}$$)
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$${3 \over 8}$$
$${3 \over 2}$$
$${2 \over 3}$$
$${4 \over 3}$$
Explanation
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$$\tan 37^\circ = {3 \over 4} = {{{{k{P_2}} \over {{r^3}}}} \over {{{2k{P_1}} \over {{r^3}}}}} = {{{P_2}} \over {2{P_1}}} = {3 \over 4}$$
$${{{P_2}} \over {{P_1}}} = {3 \over 2}$$
$${{{P_1}} \over {{P_2}}} = {2 \over 3}$$
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