JEE MAIN - Physics (2021 - 25th February Morning Shift - No. 6)
Match List - I with List - II :
Choose the correct answer from the options given below :
| List I | List II | ||
|---|---|---|---|
| (a) | h (Planck's constant) | (i) | $$[ML{T^{ - 1}}]$$ |
| (b) | E (kinetic energy) | (ii) | $$[M{L^2}{T^{ - 1}}]$$ |
| (c) | V (electric potential) | (iii) | $$[M{L^2}{T^{ - 2}}]$$ |
| (d) | P (linear momentum) | (iv) | $$[M{L^2}{I^{ - 1}}{T^{ - 3}}]$$ |
Choose the correct answer from the options given below :
(a) $$ \to $$ (ii), (b) $$ \to $$ (iii), (c) $$ \to $$ (iv), (d) $$ \to $$ (i)
(a) $$ \to $$ (i), (b) $$ \to $$ (ii), (c) $$ \to $$ (iv), (d) $$ \to $$ (iii)
(a) $$ \to $$ (iii), (b) $$ \to $$ (ii), (c) $$ \to $$ (iv), (d) $$ \to $$ (i)
(a) $$ \to $$ (iii), (b) $$ \to $$ (iv), (c) $$ \to $$ (ii), (d) $$ \to $$ (i)
Explanation
Kinetic Energy,
$${1 \over 2}m{v^2} = [M{L^2}{T^{ - 2}}]$$
Momentum,
$$mv = [ML{T^{ - 1}}]$$
Plank constant :
$$E = h\gamma $$
$$ \Rightarrow M{L^2}{T^{ - 2}} = h \times {1 \over T}$$
$$ \Rightarrow h = [M{L^2}{T^{ - 1}}]$$
Also, $$E = qV$$
$$ \Rightarrow V = {{[M{L^2}{T^{ - 2}}]} \over {[C]}} = [M{L^2}{T^{ - 2}}{C^{ - 1}}]$$
$${1 \over 2}m{v^2} = [M{L^2}{T^{ - 2}}]$$
Momentum,
$$mv = [ML{T^{ - 1}}]$$
Plank constant :
$$E = h\gamma $$
$$ \Rightarrow M{L^2}{T^{ - 2}} = h \times {1 \over T}$$
$$ \Rightarrow h = [M{L^2}{T^{ - 1}}]$$
Also, $$E = qV$$
$$ \Rightarrow V = {{[M{L^2}{T^{ - 2}}]} \over {[C]}} = [M{L^2}{T^{ - 2}}{C^{ - 1}}]$$
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