JEE MAIN - Physics (2021 - 25th February Morning Shift - No. 13)
A diatomic gas, having $${C_p} = {7 \over 2}R$$ and $${C_v} = {5 \over 2}R$$, is heated at constant pressure. The ratio dU : dQ : dW :
5 : 7 : 3
3 : 7 : 2
5 : 7 : 2
3 : 5 : 2
Explanation
$$dV = n{5 \over 2}R\Delta T$$
$$dQ = n{7 \over 2}R\Delta T$$
$$dW = dQ - dV$$
$$ = n{2 \over 2}R\Delta T$$
$$ \therefore $$ $$dV:dQ:dW$$
$$ = n{5 \over 2}R\Delta T:n{7 \over 2}R\Delta T:n{2 \over 2}R\Delta T$$
$$ = 5:7:2$$
$$dQ = n{7 \over 2}R\Delta T$$
$$dW = dQ - dV$$
$$ = n{2 \over 2}R\Delta T$$
$$ \therefore $$ $$dV:dQ:dW$$
$$ = n{5 \over 2}R\Delta T:n{7 \over 2}R\Delta T:n{2 \over 2}R\Delta T$$
$$ = 5:7:2$$
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