JEE MAIN - Physics (2021 - 25th February Evening Shift - No. 28)
A current of 6A enters one corner P of an equilateral triangle PQR having 3 wires of resistance 2$$\Omega$$ each and leaves by the corner R. The currents i1 in ampere is _________.
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Answer
2
Explanation
_25th_February_Evening_Shift_en_28_2.png)
The current $${i_1} = \left( {{{{R_2}} \over {{R_1} + {R_2}}}} \right)i$$
$$ = \left( {{2 \over {4 + 2}}} \right) \times 6$$
$${i_1} = 2A$$
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