JEE MAIN - Physics (2021 - 25th February Evening Shift - No. 27)
Two particles having masses 4 g and 16 g respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is n : 2. The value of n will be ___________.
Answer
1
Explanation
$$\because$$ relation b/w kinetic energy & momentum is
$$P = \sqrt {2mKE} $$ ($$\because$$ KE = same)
$$ \Rightarrow $$ $${{{p_1}} \over {{p_2}}} = \sqrt {{{{m_1}} \over {{m_2}}}} $$
$$ \Rightarrow $$ $${n \over 2} = \sqrt {{4 \over {16}}} $$
$$ \Rightarrow $$ $$n = 1$$
$$P = \sqrt {2mKE} $$ ($$\because$$ KE = same)
$$ \Rightarrow $$ $${{{p_1}} \over {{p_2}}} = \sqrt {{{{m_1}} \over {{m_2}}}} $$
$$ \Rightarrow $$ $${n \over 2} = \sqrt {{4 \over {16}}} $$
$$ \Rightarrow $$ $$n = 1$$
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