JEE MAIN - Physics (2021 - 25th February Evening Shift - No. 12)
Y = A sin($$\omega$$t + $$\phi$$0) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is $$Y = {A \over 2}$$ and it is moving along negative x-direction. Then the initial phase angle $$\phi$$0 will be:
$${{5\pi } \over 6}$$
$${{\pi } \over 3}$$
$${{2\pi } \over 3}$$
$${{\pi } \over 6}$$
Explanation
_25th_February_Evening_Shift_en_12_2.png)
The initial phase angle $${\phi _0} = \pi - {\pi \over 6} = {{5\pi } \over 6}$$
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