JEE MAIN - Physics (2021 - 24th February Morning Shift - No. 26)
In connection with the circuit drawn below, the value of current flowing through 2 k$$\Omega$$ resistor is _________ $$\times$$ 10$$-$$4 A.
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Answer
25
Explanation
Given, resistance, R = 2 k$$\Omega$$ = 2 $$\times$$ 103 $$\Omega$$
In Zener breakdown,
$$i = {V \over R} = {5 \over {2 \times {{10}^3}}} = 2.5 \times {10^{ - 3}}$$
$$\because$$ $$x \times {10^{ - 4}} = 25 \times {10^{ - 4}}$$
$$\therefore$$ x = 25
In Zener breakdown,
$$i = {V \over R} = {5 \over {2 \times {{10}^3}}} = 2.5 \times {10^{ - 3}}$$
$$\because$$ $$x \times {10^{ - 4}} = 25 \times {10^{ - 4}}$$
$$\therefore$$ x = 25
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