JEE MAIN - Physics (2021 - 24th February Morning Shift - No. 22)
A hydraulic press can lift 100 kg when a mass 'm' is placed on the smaller piston. It can lift ___________ kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass 'm' on the smaller piston.
Answer
25600
Explanation
According to Pascal's law,
$${{{F_1}} \over {{A_1}}} = {{{F_2}} \over {{A_2}}}$$
Initially, $${{100g} \over {{A_1}}} = {{mg} \over {{A_2}}}$$ .... (i)
Finally, $${{Mg} \over {16{A_1}}} = {{mg} \over {\left( {{{{A_2}} \over {16}}} \right)}}$$ ..... (ii)
On dividing Eqs. (i) by (ii), we get
$${{100 \times 16} \over M} = {1 \over {16}}$$
$$\therefore$$ M = 25600 kg
$${{{F_1}} \over {{A_1}}} = {{{F_2}} \over {{A_2}}}$$
Initially, $${{100g} \over {{A_1}}} = {{mg} \over {{A_2}}}$$ .... (i)
Finally, $${{Mg} \over {16{A_1}}} = {{mg} \over {\left( {{{{A_2}} \over {16}}} \right)}}$$ ..... (ii)
On dividing Eqs. (i) by (ii), we get
$${{100 \times 16} \over M} = {1 \over {16}}$$
$$\therefore$$ M = 25600 kg
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