JEE MAIN - Physics (2021 - 24th February Evening Shift - No. 8)
A body weights 49N on a spring balance at the north pole. What will be its weight recorded on the same weighing machine, if it is shifted to the equator?
[Use $$g = {{GM} \over {{R^2}}}$$ = 9.8 ms$$-$$2 and radius of earth, R = 6400 km.]
[Use $$g = {{GM} \over {{R^2}}}$$ = 9.8 ms$$-$$2 and radius of earth, R = 6400 km.]
49 N
49.83 N
48.83 N
49.17 N
Explanation
Given, weight of body at North pole,
wp = mg = 49 N
Radius of Earth, R = 6400 km
Let weight of body at equator be we.
At equator, ge = g $$-$$ R$$\omega$$2
$$\therefore$$ we = mge = m(g $$-$$ R$$\omega$$2)
Since, wp > we $$\Rightarrow$$ we < 49 N
Hence, above condition is satisfied by only option (b).
wp = mg = 49 N
Radius of Earth, R = 6400 km
Let weight of body at equator be we.
At equator, ge = g $$-$$ R$$\omega$$2
$$\therefore$$ we = mge = m(g $$-$$ R$$\omega$$2)
Since, wp > we $$\Rightarrow$$ we < 49 N
Hence, above condition is satisfied by only option (b).
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