JEE MAIN - Physics (2021 - 24th February Evening Shift - No. 4)

Figure shows a circuit that contains four identical resistors with resistance R = 2.0$$\Omega$$, two identical inductors with inductance L = 2.0 mH and an ideal battery with emf E = 9V. The current 'i' just after the switch 'S' is closed will be :

JEE Main 2021 (Online) 24th February Evening Shift Physics - Electromagnetic Induction Question 79 English
3.0 A
3.37 A
9 A
2.25 A

Explanation

Given, resistance, R = 2$$\Omega$$,

Inductance, L = 2 mH,

emf, E = 9 V

and i be the current.

$$\because$$ At t = 0 when switch is closed, inductors behave as open circuit.

$$\therefore$$ Effective circuit will be

JEE Main 2021 (Online) 24th February Evening Shift Physics - Electromagnetic Induction Question 79 English Explanation
By using Ohm's law, V = i Req

$$\Rightarrow$$ i = V/Req

where, Req is equivalent resistance of series resistors,

i.e., Req = R + R = 2R = 2 $$\times$$ 2 = 4 $$\Omega$$

$$\therefore$$ $$i = {9 \over 4} = 2.25$$A

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