JEE MAIN - Physics (2021 - 24th February Evening Shift - No. 3)
_24th_February_Evening_Shift_en_3_1.png)
The logic circuit shown above is equivalent to :
_24th_February_Evening_Shift_en_3_2.png)
_24th_February_Evening_Shift_en_3_3.png)
_24th_February_Evening_Shift_en_3_4.png)
_24th_February_Evening_Shift_en_3_5.png)
Explanation
The logic circuit is given as
_24th_February_Evening_Shift_en_3_6.png)
By using De-morgan’s theorem,
$$C = \overline {A + \overline B } = \overline A .\overline{\overline B} = \overline A .B$$
This relation can be shown by the circuit drawn below
_24th_February_Evening_Shift_en_3_7.png)
By using De-morgan’s theorem,
$$C = \overline {A + \overline B } = \overline A .\overline{\overline B} = \overline A .B$$
This relation can be shown by the circuit drawn below
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