JEE MAIN - Physics (2021 - 22th July Evening Shift - No. 9)
A nucleus with mass number 184 initially at rest emits an $$\alpha$$-particle. If the Q value of the reaction is 5.5 MeV, calculate the kinetic energy of the $$\alpha$$-particle.
5.5 MeV
5.0 MeV
5.38 MeV
0.12 MeV
Explanation
$${k_\alpha } + {k_N} = 5.5$$
$$k = {{{p^2}} \over {2m}}$$
$$ \Rightarrow {{{k_\alpha }} \over {{k_N}}} = {{180} \over 4} = 45$$
$$ \Rightarrow {k_\alpha } = {{45} \over {46}} \times 5.5$$ MeV
= 5.38 MeV
$$k = {{{p^2}} \over {2m}}$$
$$ \Rightarrow {{{k_\alpha }} \over {{k_N}}} = {{180} \over 4} = 45$$
$$ \Rightarrow {k_\alpha } = {{45} \over {46}} \times 5.5$$ MeV
= 5.38 MeV
Comments (0)
