JEE MAIN - Physics (2021 - 22th July Evening Shift - No. 4)
A porter lifts a heavy suitcase of mass 80 kg and at the destination lowers it down by a distance of 80 cm with a constant velocity. Calculate the work done by the porter in lowering the suitcase.
(take g = 9.8 ms$$-$$2)
(take g = 9.8 ms$$-$$2)
+627.2 J
$$-$$62720.0 J
$$-$$627.2 J
784.0 J
Explanation
$$W = - N \times \Delta x$$
$$ = - 80 \times 9.8 \times {{80} \over {100}}$$
$$ = - 627.2$$ J
$$ = - 80 \times 9.8 \times {{80} \over {100}}$$
$$ = - 627.2$$ J
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