JEE MAIN - Physics (2021 - 22th July Evening Shift - No. 24)
The position of the centre of mass of a uniform semi-circular wire of radius 'R' placed in x-y plane with its centre at the origin and the line joining its ends as x-axis is given by $$\left( {0,{{xR} \over \pi }} \right)$$. Then, the value of | x | is ______________.
Answer
2
Explanation
Centre of mass of half ring is located at a distance $${{2R} \over \pi }$$ from centre of the ring on its axis of symmetry so position of centre of mass in the given question will be $$\left( {0,{{xR} \over \pi }} \right)$$
$$\Rightarrow$$ | x | = 2
$$\Rightarrow$$ | x | = 2
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