JEE MAIN - Physics (2021 - 22th July Evening Shift - No. 22)
In a given circuit diagram, a 5 V zener diode along with a series resistance is connected across a 50 V power supply. The minimum value of the resistance required, if the maximum zener current is 90 mA will be __________ $$\Omega$$.
_22th_July_Evening_Shift_en_22_1.png)
Answer
500
Explanation
$$I = {{50 - {V_z}} \over R} = {5 \over {{R_L}}} + 90 \times {10^{ - 3}}$$
_22th_July_Evening_Shift_en_22_2.png)
For RL $$\to$$ $$\infty$$
R = 500$$\Omega$$
For RL $$\to$$ $$\infty$$
R = 500$$\Omega$$
Comments (0)
