JEE MAIN - Physics (2021 - 20th July Morning Shift - No. 18)
A person whose mass is 100 kg travels from Earth to Mars in a spaceship. Neglect all other objects in sky and take acceleration due to gravity on the surface of the Earth and Mars as 10 m/s2 and 4 m/s2 respectively. Identify from the below figures, the curve that fits best for the weight of the passenger as a function of time.
_20th_July_Morning_Shift_en_18_1.png)
(b)
(c)
(d)
(a)
Explanation
Given,
Acceleration due to gravity on Earth, gE = 10 m/s2
and acceleration due to gravity on Mars, gM = 4 m/s2
We know that, gE (at height h) = $${g_{Earth}}\left( {1 - {{2h} \over R}} \right)$$
$$\therefore$$ Weight at Earth, mgE = 100 $$\times$$ 10 = 1000 N
As the spaceship moves far away from Earth, the value of gE decreases to zero at a point where gE + gM = 0 and hence weight will also be zero.
This point is called neutral point and is shown by graph (c) in the given figure.
Then, gE increases 4ms$$-$$2 at Mars surface and weight becomes 400N which is also exhibited by graph (c).
Acceleration due to gravity on Earth, gE = 10 m/s2
and acceleration due to gravity on Mars, gM = 4 m/s2
We know that, gE (at height h) = $${g_{Earth}}\left( {1 - {{2h} \over R}} \right)$$
$$\therefore$$ Weight at Earth, mgE = 100 $$\times$$ 10 = 1000 N
As the spaceship moves far away from Earth, the value of gE decreases to zero at a point where gE + gM = 0 and hence weight will also be zero.
This point is called neutral point and is shown by graph (c) in the given figure.
Then, gE increases 4ms$$-$$2 at Mars surface and weight becomes 400N which is also exhibited by graph (c).
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