JEE MAIN - Physics (2021 - 20th July Evening Shift - No. 3)
A satellite is launched into a circular orbit of radius R around earth, while a second satellite is launched into a circular orbit of radius 1.02 R. The percentage difference in the time periods of the two satellites is :
1.5
2.0
0.7
3.0
Explanation
$${T^2} \propto {R^3}$$
$$T = k{R^{3/2}}$$
$${{dT} \over T} = {3 \over 2}{{dR} \over R}$$
$$ = {3 \over 2} \times 0.02 = 0.03$$
% Change = 3%
$$T = k{R^{3/2}}$$
$${{dT} \over T} = {3 \over 2}{{dR} \over R}$$
$$ = {3 \over 2} \times 0.02 = 0.03$$
% Change = 3%
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