JEE MAIN - Physics (2021 - 20th July Evening Shift - No. 25)
One mole of an ideal gas at 27$$^\circ$$ is taken from A to B as shown in the given PV indicator diagram. The work done by the system will be _________ $$\times$$ 10$$-$$1 J. [Given : R = 8.3 J/mole K, ln2 = 0.6931] (Round off to the nearest integer)
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Answer
17258
Explanation
Process of isothermal
$$W = nRT\ln \left( {{{{V_2}} \over {{V_1}}}} \right)$$
= 1 $$\times$$ 8.3 $$\times$$ 300 $$\times$$ ln2
= 17258 $$\times$$ 10$$-$$1 J
$$W = nRT\ln \left( {{{{V_2}} \over {{V_1}}}} \right)$$
= 1 $$\times$$ 8.3 $$\times$$ 300 $$\times$$ ln2
= 17258 $$\times$$ 10$$-$$1 J
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