JEE MAIN - Physics (2021 - 20th July Evening Shift - No. 19)
A zener diode having zener voltage 8 V and power dissipation rating of 0.5 W is connected across a potential divider arranged with maximum potential drop across zener diode is as shown in the diagram. The value of protective resistance Rp is .................... $$\Omega$$.
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Answer
192
Explanation
P = Vi
0.5 = 8i
i = $${1 \over {16}}$$A
E = 20 = 8 + i Rp
Rp = 12 $$\times$$ 16 = 192$$\Omega$$
0.5 = 8i
i = $${1 \over {16}}$$A
E = 20 = 8 + i Rp
Rp = 12 $$\times$$ 16 = 192$$\Omega$$
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