JEE MAIN - Physics (2021 - 20th July Evening Shift - No. 13)
The correct relation between the degrees of freedom f and the ratio of specific heat $$\gamma$$ is :
$$f = {2 \over {\gamma - 1}}$$
$$f = {2 \over {\gamma + 1}}$$
$$f = {{\gamma + 1} \over 2}$$
$$f = {1 \over {\gamma + 1}}$$
Explanation
$$\gamma = 1 + {2 \over f}$$
$$ \Rightarrow $$ $$f = {2 \over {\gamma - 1}}$$
$$ \Rightarrow $$ $$f = {2 \over {\gamma - 1}}$$
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